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49x^2-12.25=0
a = 49; b = 0; c = -12.25;
Δ = b2-4ac
Δ = 02-4·49·(-12.25)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-49}{2*49}=\frac{-49}{98} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+49}{2*49}=\frac{49}{98} =1/2 $
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